y^2-4y+10=y(y-5)

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Solution for y^2-4y+10=y(y-5) equation:


Simplifying
y2 + -4y + 10 = y(y + -5)

Reorder the terms:
10 + -4y + y2 = y(y + -5)

Reorder the terms:
10 + -4y + y2 = y(-5 + y)
10 + -4y + y2 = (-5 * y + y * y)
10 + -4y + y2 = (-5y + y2)

Add '-1y2' to each side of the equation.
10 + -4y + y2 + -1y2 = -5y + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
10 + -4y + 0 = -5y + y2 + -1y2
10 + -4y = -5y + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
10 + -4y = -5y + 0
10 + -4y = -5y

Solving
10 + -4y = -5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '5y' to each side of the equation.
10 + -4y + 5y = -5y + 5y

Combine like terms: -4y + 5y = 1y
10 + 1y = -5y + 5y

Combine like terms: -5y + 5y = 0
10 + 1y = 0

Add '-10' to each side of the equation.
10 + -10 + 1y = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 1y = 0 + -10
1y = 0 + -10

Combine like terms: 0 + -10 = -10
1y = -10

Divide each side by '1'.
y = -10

Simplifying
y = -10

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